What is the output of the following Python Program?
What is the output of the following Python Program?
The correct answer to that #pythonprogramming #quiz is 1) 1 2 Here is the explanation : 👉 For i := 1 and i := 2 , it displays i , that is 1 and 2 👉When i == 3 , the loop is broken 👉As an if has ALREADY been met, then the else is not entered. 👉If we had not had the if i == 3 then the else would have been entered And we we would have displayed " 1 2 3 4 5 Completed successfully" 👉 Conclusion : the right answer is 1 2 #python #100daysofcode #softwareengineer #programming #coding #java #javascript #programmer #developer #html #coder #code #computerscience #technology #css #pythonprogramming #linux #php #software #reptilesofinstagram #webdevelopment #webdevelop #interviewer #tech #codinglife #algorithms #algorithm #datastructures #statistics #programmers #analytics #leetcode #MachineLearning #ArtificialIntelligence #datascience #nlp #reactjs #100daysofmlcode #nlp #textprocessing #programminglife #hacking #learntocode 👉
@clcoding The answer is option a) 1,2
The correct answer is: b) 1 2 Completed successfully Explanation: The given code iterates over the elements of the list `lst` using a for loop. When the element `3` is encountered, the code breaks out of the loop using the `break` statement. As a result, the loop is terminated, and the code moves to the `else` block. In this case, since the loop was not exited due to the `break` statement, the message "Completed successfully" is printed. Therefore, the output will be "1 2 Completed successfully."
@clcoding Any django developer here, let's connect and brainstorm. Let's get geeky💻
@clcoding 1 2 The else statement in a for loop in python only returns a value if there is no execution in it's parent for loop
@clcoding The answer is A The break keyword end the loop structure so print(i) won't get executed
@clcoding A The print statement executes until the if statement condition is met and code breaks The else statement doesn’t do anything here
@clcoding A . The loop ends when the "if" conditional detects the number 3
@clcoding Guess: (C) Error : bad indent of the 'else' expression. Py out : 1 2 The 'break' statement is for the loop, not the 'if' block. And the interp. is not complaining about the 'else' expression here. So, you could say the answer is (A) (although it's missing \n) ... or (D).
