What is the output of the following Python code?
Nice and useful question here. Ans is A. {1, 2, 3, 4, 5} Let's dive in for the beginners in Python -------------- 👉 Sets in Python are an unordered collection of unique elements. This means that each element can appear in a set only once. When you perform operations on sets, the results will always contain unique elements. 👉 When, you use the `union()` method on the `my_set` object, it returns a new set containing all unique elements from both the invoking set (`my_set`) and the set passed as an argument. 👉 Let's dive deeper into the behavior of the `union()` method. When you call `union()` on a set, it does the following: - Iterates through each element of the invoking set (`my_set`). - For each element, it checks whether that element is already in the result. If it's not, the element is added to the result. Given that the result starts off as an empty set, all unique elements of the invoking set get added. - Next, it goes through each element of the argument set (`{3, 4, 5}` in this case). - Again, for each element, it checks whether that element is already in the result. If not, the element is added. --- 👉 Let's manually walk through the union operation in this specific example: 1. Start with an empty set for the result. 2. Add each element from `my_set`: `1`, `2`, `3`. The intermediate result is `{1, 2, 3}`. 3. Now, start adding elements from the argument set `{3, 4, 5}`: - `3` is already in the result set, so we move on. - `4` is not in the result set, so it's added. - `5` is not in the result set, so it's added. By the end of this operation, the result is `{1, 2, 3, 4, 5}`. --- 👉 It's worth noting that the `union()` method does not modify the original set (`my_set` in this case). Instead, it returns a new set with the union result. This adheres to the concept of immutability associated with Python sets, where certain methods produce a new set rather than altering the existing one. --- 👉 An interesting side-note: The `union()` method can be equivalently represented using the `|` operator. Therefore, `my_set.union({3, 4, 5})` is equivalent to `my_set | {3, 4, 5}`. This could make your code more concise if preferred, but both approaches are correct and largely a matter of personal or team style preference. ------------------ 👉 If you enjoyed this explanation: ✅1. Give me a follow @rohanpaul_ai for more of this every day and ✅2. Like & Retweet this tweet: ✅3. Consider subscribing to my MachineLearning YouTube channel - youtube.com/@RohanPaul-AI #python #100daysofcode #softwareengineer #programming #coding #programmer #developer #coder #code #computerscience #technology #pythonprogramming #software #webdevelopment #webdeveloper #tech #codinglife #algorithms #algorithm #datastructures #programmers #analytics #leetcode #MachineLearning #ArtificialIntelligence #datascience #nlp #100daysofmlcode #nlp #textprocessing #programminglife #hacking #learntocode #softwaredeveloper #interview
@clcoding A) {1, 2, 3, 4, 5} because union merges two sets together into one set, and sets don't have duplicate elements which is why there isn't two 3s in the result
@clcoding The 'union()' method merges sets without duplicating any. So, the answer is A
@clcoding my_set.union((3, 4, 5)) gives the same result because set.union accepts any iterable(s). Unlike the set union operator ( | ), which accepts only sets.
@clcoding {1, 2, 3, 4, 5} is the right answer!
@clcoding that is simple question, the result is A, because the union will merge two sets into one set without duplicate elements.
@clcoding The result is {1, 2, 3, 4, 5}, so the answer is A)
@clcoding the answer is A because in python sets union() method join the sets without any duplication.
@clcoding Answer is A. union() merges two sets. Since 3 is present in both sets and sets don't allow dublicates, result will be {1,2,3,4,5}
@clcoding It's answer A {1, 2, 3, 4, 5}. The result of the union is a set all distinct elements of the two sets.
