Python Coding challenge - Day 19 What is the output of the following Python code?
Answer is B; [1,4,3] This is about modifying an element in a list using index assignment 📌 A list in Python is a dynamic array, which means it allows elements to be added, modified, or removed. Python lists are implemented as over-allocated arrays; thus, they accommodate more elements than currently stored to make append operations efficient. 📌 Upon running the script, Python starts by creating a list object `my_list` containing integers `[1, 2, 3]`. Python allocates a contiguous block of memory to store these integers and maintains a pointer to this memory block. 📌 Moving to the line `my_list[1] = 4`, Python needs to update the value at index 1 of the list. Lists are zero-indexed, so the index 1 corresponds to the second element in the list. 📌 In Python, the TIme Complexity of list indexing operations are O(1) on average, because the language internally maintains an array of pointers to the list elements. The underlying CPython code simply updates the pointer at index 1 to point to the new integer object `4`. 📌 After the assignment, the list `my_list` is modified in-place, now containing `[1, 4, 3]`. The contiguous memory block (or the array of pointers) that `my_list` points to is updated, so that the second element now points to the integer object `4`. ------------------ 👉 If you enjoyed this explanation: ✅1. Checkout my recent Python book, covering 350+ Python Core concepts like this across 1300+ pages and detail analysis. 📌Book Link in my Twitter Bio ✅2. Give me a follow @rohanpaul_ai for more of these every day and like and Retweet this tweet ------------ #python #pythoncoding #learntocode #softwaredeveloper #interview #100daysofcode #softwareengineer #programming #coding #programmer #developer #code #computerscience #technology #pythonprogramming #webdevelopment #webdeveloper #codinglife #algorithms #datastructures #programmers #analytics #leetcode #MachineLearning #datascience #100daysofmlcode #programminglife
@clcoding The answer is b; [1,4,3]. When we say my_list[1], we are using the index to access the values of the list. Python indexes start from 0, 1. so the the first element of the list ie `1` is on the 0th index, the 2nd element ie `2`, is on the 1st index. So my_list[1] changes 2 to 4.
@clcoding my_list <- [1, 2, 3] So my_list[0] = 1 my_list[1] = 2 my_list[2] = 3 if, we assign 4 to my_list[1] my_list[1] <- 4 then, now my_list is: my_list = [1, 4, 3]
@clcoding B) [1,4,3]. Lists are mutable. if you had a tuple instead---TypeError: 'tuple' object does not support item assignment
@clcoding The Answer is B) [1, 4, 3] This is because the assignment "my_list[1] = 4" modifies the existing list object "my_list". In Python, lists are mutable, which means that their elements can be changed.
